To solve the system of equations:
3x - 4y = 40 --------(1)
5x - 5y = 55 --------(2)
We can use the method of substitution or the method of elimination.
Using the method of substitution:
From equation (1), we solve for x in terms of y:
3x = 40 + 4y
x = (40/3) + (4/3)y
Substituting this expression for x into equation (2), we get:
5(40/3 + (4/3)y) - 5y = 55
Multiplying through by 3 to clear the fraction:
200 + 20y - 15y = 165
Simplifying:
5y = -35
y = -7
Now we substitute this value of y into equation (1) to solve for x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -7.
Solve the system equation
3x-4y=40
5x-5y=55
1 answer