2y - x = 5
x = 2y-5
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
x^2 + y^2 - 25 = 0
Substitute 2y-5 for x in the third equation and solve for y. Insert that value into the second equation to solve for x. Check by putting both values into the third equation.
Solve the system by the substitution method. Show your work.
2y - x = 5
x2 + y2 - 25 = 0
1 answer