Solve the system by graphing.
x+y=−2
y=13x+2
A. (6, 4); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (-3,1) and (3,3). Another line is drawn from co-ordinate (-2,-4) to (6,4).
B. (−3, 1); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (-3,1) and (3,3). Another line is drawn from co-ordinate (-4,2) to (2,-4). They intersect each other at (-3,1).
C. (3, 1); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (0,2) and (3,1). Another line is drawn from co-ordinate (-2,-4) to (6,4). They intersect each other at (3,1).
D. (0, −2); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (0,-2) and (3,-1). Another line is drawn from co-ordinate (-2,-4) to (5,3). They intersect each other at (0,-2).
4 answers
Which choice matches your findings?
x+y=−2
y=13x+2
You know it is a 2-D graph
The lines intersect at (-2/7,-12/7), so none of the choices listing a different intersection can be right. That leaves only (A).
Now you just have to check to see whether the lines pass through the named points.
No luck there. I suspect a typo in the equations.