first of all do you have a graphing calculator?
Well using my TI-83
and keying in the equations I got
(1,3) at the intersection of the 2 lines
but for the y intercept it was aproximately
(0,6)
Solve the system by graphing.
3x+y=6
3x-y=0
This is how far I got:
(First line): y=-3x+6
(Second line): y=3x
I'm not sure how to graph the second line. Is the y-intercept (0,0) and the two lines meet at (1,3)?
2 answers
No, I don't have a graphing calculator. Thanks for your help.
2 answers