multiply the 2nd equation by 5 and you have
3x-5y = 21
10x+5y = 5
Now you can eliminate y and get x, then figure y.
Solve the system by either substitution or elimination
3x-5y=21
2x+y=1
A (2,-3)
B (2,3)
C (-2,-1)
D (-2,1)
3 answers
a (2, -3)
thanks you for helpful explanation