Solve the system by addition or substitution.

Question

3x – 4y = 8
6x – 2y = 10

Please get me on the correct track

for 3x -4y =8
x=4, y=1
for 6x - 2y =10
x= 2, y= 1

Solve one equation for x.

3x = 4y + 8

x = (4y + 8)/3

Insert that value for x in the other equation and solve for y. Once you find the value for y, substitute that value in the same original equation and solve for x. Check by putting both values into the equations.

I hope this helps. Thanks for asking.

Answer 1

The common thing to do is multiplying both sides of the first equation by 2 to have an equal numbers of x in both of the equations:
$$
6x - 8y = 16 \\
6x - 2y = 10
$$
Now we can subtract the second equation from the first one:
$$
6y=6
$$
So, y = 6/6=1.

Now we can substitute the value of y in either of the equations to find out the value of x. Let's use the first equation.
$$
3x- 4(1) = 8
$$
So
$$
3x = 12
$$
Which means x=12/3=4.

Therefore, the solution is x = 4 and y = 1.