Asked by Anonymous-2

solve the system by addition method
7x^2+y^2=49
7x^2-y^2=49
Answered by Damon
14 x^2 = 2*49

x^2 = 7
x = +/- 7

using x = +7
7*49 + y^2 = 49
y^2 = -6 *49 no real solution
using x = -7
same answer, no real solution
Answered by Reiny
from Damon's
x^2 = 7
next line:
x = ± √7

subbing that into the first
49 + y^2 = 49
y = 0

you have an ellipse intersecting a hyperbola.
They meet at (√7,0) and (-√7,0)
Answered by adam
will the answer look like
{(0,7),(0,-7)} or {(0,ratical 7),(0,-ratical 7)}
Answered by Reiny
no, only the two points
(sqrt 7,0) and (-sqrt 7,0) work in both equations.

your solution of {(0,7),(0,-7)} works only in the first equation
{(0,ratical 7),(0,-ratical 7)} doesn't work for either one of them.

the hyperbola has the x-axis as its axis of symmetry, opens up 'sideways' and never crosses the y-axis.

BTW, does √7 show up as
the square root sign of 7 on your computer ?


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