arrange the second to
8x - 14y = -10
divide by 2
4x - 7y = -5
when you subtract the two you would get
0 = 10 , which of course is nonsense.
So the system has no solution (since both x's and y's dropped out and we ended up with a false statement)
What the "system" was trying to do was finding out where two parallel lines would meet. (they don't)
Solve the system
4x - 7y = 5
14y = 8x + 10
I got y = 10/-13
x = -5/52
but it doesn't seem right
5 answers
For 8x - 14 y = 10
wouldn't it be 10 and not -10?
wouldn't it be 10 and not -10?
the way I learned it was to solve for x first and then put the equation for x into the second equation to get y.
ok, let's do it your way....
1st:
4x - 7y = 5
4x = 7y + 5
x = (7y+5)/4
into the 2nd:
14y = 8(7y+5)/4 + 10
14y = 2(7y+5)
14y = 14y + 10
0 = 10
same result!!!
As to your first question in this reply ...
14y = 8x + 10
14y - 8x = 10 , multiply by -1
-14y + 8x = -10 or
8x - 14y = -10
1st:
4x - 7y = 5
4x = 7y + 5
x = (7y+5)/4
into the 2nd:
14y = 8(7y+5)/4 + 10
14y = 2(7y+5)
14y = 14y + 10
0 = 10
same result!!!
As to your first question in this reply ...
14y = 8x + 10
14y - 8x = 10 , multiply by -1
-14y + 8x = -10 or
8x - 14y = -10
thank you!