Solve the simultaneous equation using substitution method:4x = y + 7and 3x + 4y + 9 = 0
6 answers
I dont understand how to solve it
Standard form:
4x-y = 7.
3x+4y = -9.
Multiply first Eq by 4 and add the Eqs.:
16x-4y = 28
3x+4y = -9
sum: 19x = 19
X = 1.
In Eq2, replace x with 1 and solve for y:
3*1+4y = -9
4x-y = 7.
3x+4y = -9.
Multiply first Eq by 4 and add the Eqs.:
16x-4y = 28
3x+4y = -9
sum: 19x = 19
X = 1.
In Eq2, replace x with 1 and solve for y:
3*1+4y = -9
By substitution:
form 4x = y + 7 ---> y = 4x - 7
into the 2nd:
3x + 4(4x-7) + 9 = 0
19x = 19
x = 1
then y = 4(1) - 7 = -3
form 4x = y + 7 ---> y = 4x - 7
into the 2nd:
3x + 4(4x-7) + 9 = 0
19x = 19
x = 1
then y = 4(1) - 7 = -3
8y+42=7and6y-82=41
What is the correct answer
5a-ab=-1 and 3a+4b=-2
8 answers