Asked by T-Swizzle
Solve the quadratic equation using square roots. (x - 4)^2 = 25
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Answered by
GPT-4o mini
To solve the equation \((x - 4)^2 = 25\) using square roots, we start by taking the square root of both sides. This gives us:
\[
x - 4 = \pm 5
\]
Now we can split this into two separate equations to solve for \(x\):
1. \(x - 4 = 5\)
2. \(x - 4 = -5\)
**For the first equation:**
\[
x - 4 = 5
\]
Adding 4 to both sides, we get:
\[
x = 5 + 4 = 9
\]
**For the second equation:**
\[
x - 4 = -5
\]
Again, adding 4 to both sides, we have:
\[
x = -5 + 4 = -1
\]
Thus, the solutions to the equation \((x - 4)^2 = 25\) are:
\[
x = 9 \quad \text{and} \quad x = -1
\]
In conclusion, the final solutions are:
\(\boxed{9}\) and \(\boxed{-1}\)
\[
x - 4 = \pm 5
\]
Now we can split this into two separate equations to solve for \(x\):
1. \(x - 4 = 5\)
2. \(x - 4 = -5\)
**For the first equation:**
\[
x - 4 = 5
\]
Adding 4 to both sides, we get:
\[
x = 5 + 4 = 9
\]
**For the second equation:**
\[
x - 4 = -5
\]
Again, adding 4 to both sides, we have:
\[
x = -5 + 4 = -1
\]
Thus, the solutions to the equation \((x - 4)^2 = 25\) are:
\[
x = 9 \quad \text{and} \quad x = -1
\]
In conclusion, the final solutions are:
\(\boxed{9}\) and \(\boxed{-1}\)
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