To solve the quadratic equation \(12x^2 + 20x = 0\), we start by factoring out the greatest common factor (GCF) from the expression.
- Identify the GCF of the coefficients \(12\) and \(20\). The GCF is \(4\). So, we factor out \(4x\):
\[ 12x^2 + 20x = 4x(3x + 5) = 0 \]
- Set each factor equal to zero:
\[ 4x = 0 \quad \text{and} \quad 3x + 5 = 0 \]
- Solve the first equation:
\[ 4x = 0 \implies x = 0 \]
- Solve the second equation:
\[ 3x + 5 = 0 \implies 3x = -5 \implies x = -\frac{5}{3} \]
Now we can write the solutions. The smaller solution should be listed first:
- Smaller solution: \(x = -\frac{5}{3}\)
- Larger solution: \(x = 0\)
In summary:
GCF: \(4x\)
List smaller solution first:
- \(x = -\frac{5}{3}\)
- \(x = 0\)