To solve the quadratic equation \(x^2 - 6x - 5 = 0\) by completing the square, we first rearrange the equation to complete the square.
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Move the constant term to the other side of the equation: \[ x^2 - 6x = 5 \]
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To complete the square, take half of the coefficient of \(x\) (which is \(-6\)), square it, and add it to both sides. Half of \(-6\) is \(-3\), and squaring it gives \(9\): \[ x^2 - 6x + 9 = 5 + 9 \] \[ x^2 - 6x + 9 = 14 \]
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Now, we can factor the left side: \[ (x - 3)^2 = 14 \]
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Take the square root of both sides to solve for \(x\): \[ x - 3 = \pm \sqrt{14} \]
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Solve for \(x\) by adding 3 to both sides: \[ x = 3 \pm \sqrt{14} \]
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Now, we find the numerical values for the solutions, rounding to the nearest hundredth:
- First solution: \[ x_1 = 3 + \sqrt{14} \approx 3 + 3.7417 \approx 6.7417 \approx 6.74 \]
- Second solution: \[ x_2 = 3 - \sqrt{14} \approx 3 - 3.7417 \approx -0.7417 \approx -0.74 \]
Form:
The completed square form would be \((x - 3)^2 = 14\).
Solution:
The solutions are: \[ x = 6.74, -0.74 \]
So we can write: Solution: \(X = 6.74, -0.74\).