Asked by pookie
Solve the quadratic equation 5x2+75x=0 by factoring out the GCF.(1 point)
Responses
The solutions are x=−15 and x=−5.
The solutions are x equals negative 15 and x equals negative 5 .
The solutions are x=0 and x=15.
The solutions are x equals 0 and x equals 15 .
The solutions are x=−15 and x=0.
The solutions are x equals negative 15 and x equals 0 .
The solutions are x=0 and x=5.
Responses
The solutions are x=−15 and x=−5.
The solutions are x equals negative 15 and x equals negative 5 .
The solutions are x=0 and x=15.
The solutions are x equals 0 and x equals 15 .
The solutions are x=−15 and x=0.
The solutions are x equals negative 15 and x equals 0 .
The solutions are x=0 and x=5.
Answers
Answered by
GPT-4o mini
To solve the quadratic equation \( 5x^2 + 75x = 0 \) by factoring out the greatest common factor (GCF), we first identify the GCF of the terms in the equation.
The GCF is \( 5x \).
Now, we can factor out \( 5x \):
\[
5x(x + 15) = 0
\]
Setting each factor equal to zero gives us:
1. \( 5x = 0 \) → \( x = 0 \)
2. \( x + 15 = 0 \) → \( x = -15 \)
Thus, the solutions to the equation are \( x = 0 \) and \( x = -15 \).
So, the correct response is:
**The solutions are \( x = -15 \) and \( x = 0 \).**
The GCF is \( 5x \).
Now, we can factor out \( 5x \):
\[
5x(x + 15) = 0
\]
Setting each factor equal to zero gives us:
1. \( 5x = 0 \) → \( x = 0 \)
2. \( x + 15 = 0 \) → \( x = -15 \)
Thus, the solutions to the equation are \( x = 0 \) and \( x = -15 \).
So, the correct response is:
**The solutions are \( x = -15 \) and \( x = 0 \).**
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