To solve the quadratic equation \(46x^2 - 138x = 0\) by factoring out the greatest common factor (GCF), we first identify the GCF of the terms.
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The GCF of \(46x^2\) and \(-138x\) is \(46x\).
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We can factor out \(46x\) from the equation:
\[ 46x(x - 3) = 0 \]
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Now we can set each factor equal to zero:
\[ 46x = 0 \quad \text{or} \quad x - 3 = 0 \]
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Solving these gives us:
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From \(46x = 0\): \[ x = 0 \]
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From \(x - 3 = 0\): \[ x = 3 \]
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Thus, the solutions to the equation are \(x = 0\) and \(x = 3\).
The correct response is:
The solutions are \(x = 0\) and \(x = 3\).