(2x-1)^2=0
2x-1=0
x=1/2
in the next equation, it is a degree two equation, it has two solutions
x=(-4+-sqrt(16+12*7)/6= 1 and 2/3
Solve the quadratic equation 2x² - 4x + 1 = 0
How many solutions are in the equation 3x² + 4x - 7 = 0
2 answers
2x² - 4x + 1 = 0
use the formula
x = (4 ± √(16 - 4(2)(1) )/4
= 3 ± √8)/4
= ...... , simplify it a bit more, remember √8 = 2√2
for the 2nd,
remember that the b^2 - 4ac of the formula is called the
discriminant,
if b^2 - 4ac > 0 there will be 2 and distinct roots
if b^2 - 4ac = 0 there will be 1 real root, actually 2 equal roots
if b^2 - 4ac < 0 you will have 2 different complex roots, one being the conjugate of the other.
use the formula
x = (4 ± √(16 - 4(2)(1) )/4
= 3 ± √8)/4
= ...... , simplify it a bit more, remember √8 = 2√2
for the 2nd,
remember that the b^2 - 4ac of the formula is called the
discriminant,
if b^2 - 4ac > 0 there will be 2 and distinct roots
if b^2 - 4ac = 0 there will be 1 real root, actually 2 equal roots
if b^2 - 4ac < 0 you will have 2 different complex roots, one being the conjugate of the other.
1 answer