(a) use the quadratic formula
(b) the discriminant is positive, so two real roots
Solve the quadratic equation 2x² - 4x + 1 = 0
How many solutions are in the equation 3x² + 4x - 7 = 0
2 answers
1. 2x^2 - 4x + 1 = 0,
X = (-B +- sqrt(B^2-4AC))/2A,
X = (4 +- sqrt(16 - 8))/4 = 1.71, and 0.294.
2. 3x^2 + 4x - 7 = 0,
B^2 - 4AC = 16 + 84 = 100,
The discriminant is positive; therefore, we have 2 real solutions.
X = (-B +- sqrt(B^2-4AC))/2A,
X = (4 +- sqrt(16 - 8))/4 = 1.71, and 0.294.
2. 3x^2 + 4x - 7 = 0,
B^2 - 4AC = 16 + 84 = 100,
The discriminant is positive; therefore, we have 2 real solutions.
1 answer