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solve the quadratic equation 2x^4-3x^3-7x^2 12x-4=0

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well, if you meant

2x^4-3x^3-7x^2+12x-4, it is a quartic, but can easily be factored into two quadratic factors.

It is (x^2-4)(2x^2-3x+1)

which are both easily solved.

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