To solve the quadratic equation, we can subtract 3 from both sides of the equation to get:
10x^2 - 2x + 10 = 0
Now, we can use the quadratic formula to find the solutions:
x = (-b ± √(b^2 - 4ac))/(2a)
Plugging in the values a = 10, b = -2, and c = 10, we get:
x = (-(-2) ± √((-2)^2 - 4(10)(10))) / (2(10))
x = (2 ± √(4 - 400)) / 20
x = (2 ± √(-396)) / 20
Since the discriminant (√(b^2 - 4ac)) is negative, the solutions will be complex numbers. Therefore, the correct answer is: 110±311√10i.
Solve the quadratic equation 10x2−2x+13=3 . Which of the following expresses its solutions in the form a±bi ?(1 point) Responses 15±311√5i Start Fraction 1 over 5 End Fraction plus or minus Start Fraction 3 Start Root 11 End Root over 5 End Fraction i 110±101√10i Start Fraction 1 over 10 End Fraction plus or minus Start Fraction Start Root 101 End Root over 10 End Fraction i −110±311√10i negative Start Fraction 1 over 10 End Fraction plus or minus Start Fraction 3 Start Root 11 End Root over 10 End Fraction i 110±311√10i
1 answer