To solve this problem, we need to find the value of n.
In base n, the number 132 is equal to 1*n^2 + 3*n^1 + 2*n^0.
In base ten, the number 72 is equal to 7*10^1 + 2*10^0.
Setting these two expressions equal, we get:
1*n^2 + 3*n^1 + 2*n^0 = 7*10^1 + 2*10^0
Re-arranging the equation, we have:
1*n^2 + 3*n - 68 = 0
To solve for n, we can use the quadratic formula:
n = (-3 ± √(3^2 - 4*1*(-68))) / (2*1)
n = (-3 ± √(9 + 272)) / 2
n = (-3 ± √281) / 2
Therefore, the value of n is approximately -9.36 or 6.36, since n cannot be negative in this case.
Solve the problem 132 base (n)=72 base ten
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