Differentiate s(t). The derivative, ds/dt, is the speed as a function of t.
ds/dt = [(1/2)/sqrt(5 +4t)]*4
= 2/sqrt(5+4t)
At t = 1, this equals 2/(sqrt9) = 2/3
Solve:
The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds.
Find the particle's velocity at t=1 sec.
A) 2/3 m/sec
B) 4/3 m/sec
C) -1/3 m/sec
D) 1/6 m/sec
Thank you!
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