Solve the pair of equations simultaneously:

1) 2x+y=3,4x^2 y^2 +2x+3y=16
2) 2^2x-3y=4,3^3x+5y 18=0

1 answer

1) To solve the pair of equations simultaneously, we can rearrange the first equation to solve for y:

2x + y = 3
y = 3 - 2x

Substituting this into the second equation:

4x^2(y^2) + 2x + 3y = 16
4x^2((3 - 2x)^2) + 2x + 3(3 - 2x) = 16
4x^2(9 - 12x + 4x^2) + 2x + 9 - 6x = 16
36x^2 - 48x^3 + 16x^4 + 2x + 9 - 6x = 16
16x^4 - 48x^3 + 36x^2 - 4x - 7 = 0

Unfortunately, this leads to a quartic equation which is difficult to solve analytically. We would need to use numerical methods or graphing software to find the solutions.

2) The second equation is missing an equal sign so we cannot solve it as given.
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