To solve the expression \( 6 - 4(3 - 1)^2 + 16 \), we will follow the order of operations which is PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).
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Calculate inside the parentheses: \[ 3 - 1 = 2 \]
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Evaluate the exponent: \[ (2)^2 = 4 \]
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Multiply by -4: \[ -4 \times 4 = -16 \]
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Substitute back into the expression: \[ 6 - 16 + 16 \]
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Perform the addition and subtraction from left to right: \[ 6 - 16 = -10 \] \[ -10 + 16 = 6 \]
So, the final result is: \[ \boxed{6} \]