so sqrt { x+7} = 1 right?
if so... then square both sides to get x+7 =1
x = -6
solve the logarithmic equation. Be sure to reject any value of x that is not in the domain.
In square root x+7=1
x= ?
What is the decimal approximation to the solution?
x= ?
2 answers
I think Knights missed the "ln" in front
ln √(x+7) = 1
√(x+7) = e^1 = e
square both sides
x+7 = e^2
x = e^2 - 7
x = appr .389
ln √(x+7) = 1
√(x+7) = e^1 = e
square both sides
x+7 = e^2
x = e^2 - 7
x = appr .389
1 answer