Solve the linear system: y= -2x+8

Question

3x-4y=12

Answer 1

To solve this system, we can use the method of substitution.

First, let's solve for y in terms of x in the first equation:
y = -2x + 8

Next, substitute this expression for y in the second equation:
3x - 4(-2x + 8) = 12

Simplify the equation:
3x + 8x - 32 = 12
11x - 32 = 12

Move the constant term to the other side:
11x = 12 + 32
11x = 44

Divide both sides by 11:
x = 44/11
x = 4

Now, substitute this value of x back into the first equation to solve for y:
y = -2(4) + 8
y = -8 + 8
y = 0

Therefore, the solution to the linear system is x = 4 and y = 0.