To solve the inequality \( \frac{1}{3}x - 1 > 2 \), follow these steps:
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Add 1 to both sides to isolate the term with \( x \): \[ \frac{1}{3}x > 2 + 1 \] \[ \frac{1}{3}x > 3 \]
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Multiply both sides by 3 to eliminate the fraction: \[ x > 3 \cdot 3 \] \[ x > 9 \]
So, the solution to the inequality is: \[ x > 9 \]