To solve the inequality \( \frac{1}{2}x + 1 > 9 \), follow these steps:
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Subtract 1 from both sides: \[ \frac{1}{2}x > 9 - 1 \] \[ \frac{1}{2}x > 8 \]
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Multiply both sides by 2 to isolate \( x \): \[ x > 16 \]
So, the solution to the inequality is: \[ x > 16 \]