Use the discriminant to determine how many real-number solutions the equation has.
v^2 - 7v + 5 = 0
solve the linear equation
-10.8x + 1.4 = -47.6 - 1.0x
4 answers
jessica, bring the x terms together and the simple numbers together, then you can just divide across:
-10.8x + 1.4 = -47.6 - 1.0x
-10.8x + 1.0x = -47.6 - 1.4
-9.8x = -49
x = -49/-9.8
Check my arithmetic, and finish from there.
-10.8x + 1.4 = -47.6 - 1.0x
-10.8x + 1.0x = -47.6 - 1.4
-9.8x = -49
x = -49/-9.8
Check my arithmetic, and finish from there.
chandice, it's better to post a new message when you have a new question.
Anyway, the discriminant of a quadratic is b^2-4ac, the bit inside the square root sign of the quadratic formula.
In this case:
b^2-4ac
=7^2-4*5
which is greater than zero. What does that tell you about the roots?
Anyway, the discriminant of a quadratic is b^2-4ac, the bit inside the square root sign of the quadratic formula.
In this case:
b^2-4ac
=7^2-4*5
which is greater than zero. What does that tell you about the roots?
how many real-number solutions does the equation have?
2 answers