Solve the inital value problem for y as a function of x given: dy/dx=2x-6 with an inital condition of y=4 when x=1.
antiderivative->x^2-6x+c
4=1^2-6(1)+c
c=9
y-x^2-6x+9
4 answers
see previous solution
Do you mean c=9?
yes, your solution is correct, except write it up this way:
dy/dx = 2x-6
y = x^2 - 6x + c and then proceed as you did before
dy/dx = 2x-6
y = x^2 - 6x + c and then proceed as you did before
I didn't realize I put y- instead of y=. So, you mean write it y=x^2-6x+9?
2 answers