To solve the inequality \( y \leq -\frac{2}{3}x + 1 \) by graphing, we first need to graph the related equation \( y = -\frac{2}{3}x + 1 \).
Steps to Graph the Equation:
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Identify the intercepts:
- Y-intercept: Set \( x = 0 \). \[ y = -\frac{2}{3}(0) + 1 = 1 \quad \Rightarrow \quad (0, 1) \]
- X-intercept: Set \( y = 0 \). \[ 0 = -\frac{2}{3}x + 1 \quad \Rightarrow \quad \frac{2}{3}x = 1 \quad \Rightarrow \quad x = \frac{3}{2} = 1.5 \quad \Rightarrow \quad (1.5, 0) \]
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Plot the points:
- Plot the points \( (0, 1) \) and \( (1.5, 0) \) on the coordinate plane.
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Draw the line:
- Since the inequality is \( \leq \), we will draw a solid line through these points because it includes the points on the line (the inequality includes equality).
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Shade the appropriate region:
- Since the inequality is \( y \leq -\frac{2}{3}x + 1 \), we shade the region below the line.
Conclusion:
From your description, the graph that meets the conditions of the inequality, showing a solid line (not dashed), with the correct shading below the line and intersecting the axes at \( (0, 1) \) and \( (1.5, 0) \), is what represents the inequality.
The correct response would look similar to the third description (but with a solid line) since it shows the line sloping downward from left to right, and shading that reflects the region where \( y \) is less than or equal to the line equation.