Question
Solve the inequality. Graph the solutions.
StartAbsoluteValue StartFraction x plus 15 Over 5 EndFraction EndAbsoluteValue
x+15
5greater than>3
Question content area bottom
Part 1
Select the correct choice below and fill in any answer boxes in your choice.
A.
The solution is xequals=enter your response here. (Type an integer or a simplified fraction.)
B.
The solution is enter your response hereless than<xless than<enter your response here. (Type integers or simplified fractions.)
C.
The solution is xless than<enter your response here or xgreater than>enter your response here. (Type integers or simplified fractions.)
D.
The solution is all real numbers.
E.
There is no solution.
StartAbsoluteValue StartFraction x plus 15 Over 5 EndFraction EndAbsoluteValue
x+15
5greater than>3
Question content area bottom
Part 1
Select the correct choice below and fill in any answer boxes in your choice.
A.
The solution is xequals=enter your response here. (Type an integer or a simplified fraction.)
B.
The solution is enter your response hereless than<xless than<enter your response here. (Type integers or simplified fractions.)
C.
The solution is xless than<enter your response here or xgreater than>enter your response here. (Type integers or simplified fractions.)
D.
The solution is all real numbers.
E.
There is no solution.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the inequality
\[
\left| \frac{x + 15}{5} \right| > 3,
\]
we start by breaking it down into two separate cases, based on the definition of absolute value.
### Case 1:
\[
\frac{x + 15}{5} > 3
\]
Multiply both sides of the inequality by 5 (since 5 is a positive number, the direction of the inequality does not change):
\[
x + 15 > 15.
\]
Subtract 15 from both sides:
\[
x > 0.
\]
### Case 2:
\[
\frac{x + 15}{5} < -3
\]
Again, multiply both sides by 5:
\[
x + 15 < -15.
\]
Subtract 15 from both sides:
\[
x < -30.
\]
### Combining the Results:
From both cases, we find:
1. \( x > 0 \)
2. \( x < -30 \)
Thus, the solution to the inequality is:
\[
x < -30 \quad \text{or} \quad x > 0.
\]
### Answer Selection:
The correct choice based on the results is:
C. The solution is \(x < -30\) or \(x > 0\).
### Graph the Solutions:
To graph the solutions:
- Draw a number line.
- Shade to the left of -30 to represent \(x < -30\).
- Shade to the right of 0 to represent \(x > 0\).
This visual representation shows that the solutions include all values less than -30 and all values greater than 0.
\[
\left| \frac{x + 15}{5} \right| > 3,
\]
we start by breaking it down into two separate cases, based on the definition of absolute value.
### Case 1:
\[
\frac{x + 15}{5} > 3
\]
Multiply both sides of the inequality by 5 (since 5 is a positive number, the direction of the inequality does not change):
\[
x + 15 > 15.
\]
Subtract 15 from both sides:
\[
x > 0.
\]
### Case 2:
\[
\frac{x + 15}{5} < -3
\]
Again, multiply both sides by 5:
\[
x + 15 < -15.
\]
Subtract 15 from both sides:
\[
x < -30.
\]
### Combining the Results:
From both cases, we find:
1. \( x > 0 \)
2. \( x < -30 \)
Thus, the solution to the inequality is:
\[
x < -30 \quad \text{or} \quad x > 0.
\]
### Answer Selection:
The correct choice based on the results is:
C. The solution is \(x < -30\) or \(x > 0\).
### Graph the Solutions:
To graph the solutions:
- Draw a number line.
- Shade to the left of -30 to represent \(x < -30\).
- Shade to the right of 0 to represent \(x > 0\).
This visual representation shows that the solutions include all values less than -30 and all values greater than 0.
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