Solve the inequality \\(\\frac{2z+3}{z+2}\\|eq 1\\)

Answer 1

or, in real math.

(2z+3)/(z+2) = 1
2z+3 = z+2
z = -1

I know you mentioned an inequality, but all I see is "eq" which I interpreted as "=". But I'm sure you can make any changes necessary.