10y + 40 ≥ 2y + 8
Subtract 2y from both sides:
8y + 40 ≥ 8
Subtract 40 from both sides:
8y ≥ -32
Divide by 8 on both sides:
y ≥ -4
Therefore, the solution for the inequality is y ≥ -4.
Solve the inequality for y.
5(2y + 8) >= 2y + 8
3 answers
Solve the inequality for v.
11 > - 4(4 - nu) + 5v
11 > - 4(4 - nu) + 5v
11 > -4(4 - v) + 5v
11 > -16 + 4v + 5v
11 > -16 + 9v
27 > 9v
Divide by 9 on both sides:
3 > v
Therefore, the solution for the inequality is v < 3.
11 > -16 + 4v + 5v
11 > -16 + 9v
27 > 9v
Divide by 9 on both sides:
3 > v
Therefore, the solution for the inequality is v < 3.