x^4 < 16x^2
x^2(x^2 - 16) < 0
x^2 is always positive, so
x^2 < 16
so, for -4 < x < 4
x^4 < 16x^2
at x=0, x^4 = 16x^2, so 0 is excluded from the solution
Solve the inequality. Express your solution using notation and please show all of your work.
x^4<16x^2
1 answer