Solve the inequality Ay+3<12 , where A is a number greater than 0

Answer 1

To solve the inequality \( Ay + 3 < 12 \) where \( A \) is a positive number, we'll start by isolating \( y \).

1. Subtract 3 from both sides of the inequality: \[ Ay < 12 - 3 \] This simplifies to: \[ Ay < 9 \]

2. Now, divide both sides of the inequality by \( A \). Since \( A > 0 \), the direction of the inequality remains the same: \[ y < \frac{9}{A} \]

Therefore, the solution to the inequality is: \[ y < \frac{9}{A} \]

This means that \( y \) can take any value less than \( \frac{9}{A} \).