Solve the inequality Ay+3<12

, where A
is a number greater than 0.(1 point)
y
over A

1 answer

To solve the inequality \( Ay + 3 < 12 \), where \( A > 0 \), we will first isolate \( y \).

  1. Start with the given inequality: \[ Ay + 3 < 12 \]

  2. Subtract 3 from both sides: \[ Ay < 12 - 3 \] \[ Ay < 9 \]

  3. Divide both sides by \( A \) (since \( A > 0 \), the direction of the inequality does not change): \[ y < \frac{9}{A} \]

Thus, the solution to the inequality is: \[ y < \frac{9}{A} \]

This means that \( y \) can take any value less than \( \frac{9}{A} \).