To solve the inequality \( Ay + 3 < 12 \), where \( A > 0 \), we will first isolate \( y \).
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Start with the given inequality: \[ Ay + 3 < 12 \]
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Subtract 3 from both sides: \[ Ay < 12 - 3 \] \[ Ay < 9 \]
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Divide both sides by \( A \) (since \( A > 0 \), the direction of the inequality does not change): \[ y < \frac{9}{A} \]
Thus, the solution to the inequality is: \[ y < \frac{9}{A} \]
This means that \( y \) can take any value less than \( \frac{9}{A} \).