Solve the inequality Ay + 3 < 12, where A is a number greater than 0.

Question

y __ __ over A

Answer 1

To solve the inequality \( Ay + 3 < 12 \) where \( A \) is a positive number, we can follow these steps:

1. Isolate the term with \( y \): \[ Ay < 12 - 3 \] \[ Ay < 9 \]

2. Divide both sides by \( A \) (since \( A > 0\), the inequality sign remains the same): \[ y < \frac{9}{A} \]

Thus, the solution in terms of \( y \) is: \[ y < \frac{9}{A} \]

So, the answer can be expressed as: \[ y , < , \frac{9}{A} \]