Question
Solve the inequality and graph the solution on the line provided.
minus, 13, plus, 2, x, is greater than or equal to, minus, 15
−13+2x≥
−15
Answer
Attempt 1 out of 2
Inequality Notation:
Number Line:
minus, 13, plus, 2, x, is greater than or equal to, minus, 15
−13+2x≥
−15
Answer
Attempt 1 out of 2
Inequality Notation:
Number Line:
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the inequality \(-13 + 2x \geq -15\), follow these steps:
1. **Isolate the variable \(x\)**:
\[
-13 + 2x \geq -15
\]
First, add \(13\) to both sides:
\[
2x \geq -15 + 13
\]
Simplifying the right side gives:
\[
2x \geq -2
\]
2. **Divide by 2**:
Now, divide both sides by \(2\):
\[
x \geq -1
\]
So the solution to the inequality is:
\[
x \geq -1
\]
### Inequality Notation:
The solution in inequality notation is:
\[
x \geq -1
\]
### Number Line Representation:
On a number line, you would represent this as follows:
- Draw a number line.
- Mark the point \(-1\) with a closed dot (because the inequality includes \(-1\)).
- Shade the region to the right of \(-1\) (to indicate all values greater than or equal to \(-1\)).
Here's a simple representation of the number line:
```
<---|----|-----|-----|-----|-----|-----|-----|-----|---->
-3 -2 -1 0 1 2 3
●------> (shaded to the right)
```
Where \(-1\) is marked with a closed dot.
1. **Isolate the variable \(x\)**:
\[
-13 + 2x \geq -15
\]
First, add \(13\) to both sides:
\[
2x \geq -15 + 13
\]
Simplifying the right side gives:
\[
2x \geq -2
\]
2. **Divide by 2**:
Now, divide both sides by \(2\):
\[
x \geq -1
\]
So the solution to the inequality is:
\[
x \geq -1
\]
### Inequality Notation:
The solution in inequality notation is:
\[
x \geq -1
\]
### Number Line Representation:
On a number line, you would represent this as follows:
- Draw a number line.
- Mark the point \(-1\) with a closed dot (because the inequality includes \(-1\)).
- Shade the region to the right of \(-1\) (to indicate all values greater than or equal to \(-1\)).
Here's a simple representation of the number line:
```
<---|----|-----|-----|-----|-----|-----|-----|-----|---->
-3 -2 -1 0 1 2 3
●------> (shaded to the right)
```
Where \(-1\) is marked with a closed dot.
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