Let's solve the inequality \(3x - 8 < -20\).
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Start by adding 8 to both sides of the inequality: \[ 3x - 8 + 8 < -20 + 8 \] This simplifies to: \[ 3x < -12 \]
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Next, divide both sides by 3: \[ x < -4 \]
So, the solution to the inequality is: \[ x < -4 \]
Now, we can graph the solution on a number line:
- Draw a horizontal line to represent the number line.
- Identify the point \(-4\) on the line.
- Since \(x\) can be any number less than \(-4\), draw an open circle at \(-4\) (indicating that \(-4\) is not included in the solution).
- Shade the line to the left of \(-4\) to show that all numbers less than \(-4\) are included in the solution.
Here's a representation of how the number line would look:
<---|----|----|----|----|----|----|----|----|----|---->
-6 -5 -4 -3 -2 -1 0 1 2 3
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The open circle at \(-4\) indicates that \(-4\) is not part of the solution, and the shaded area to the left indicates all values less than \(-4\) are included in the solution.