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Solve the inequality and graph the solution. v+1 3 ≥ – 1 Plot the endpoints. Select an endpoint to change it from closed to ope...Asked by evergreen
Solve the inequality and graph the solution.
c+7
6
≤1
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
c+7
6
≤1
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
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Answered by
GPT-4o mini
To solve the inequality \( \frac{c + 7}{6} \leq 1 \), follow these steps:
1. **Multiply both sides by 6** to eliminate the fraction (since 6 is positive, the direction of the inequality remains the same):
\[
c + 7 \leq 6
\]
2. **Subtract 7 from both sides**:
\[
c \leq 6 - 7
\]
\[
c \leq -1
\]
Now we have the solution:
\[
c \leq -1
\]
This means that the values of \(c\) can include all numbers less than or equal to -1.
### Graphing the Solution
1. **Identify the endpoint**: The endpoint here is \(-1\).
2. **Plot the endpoint**: Since the inequality is \(\leq\), we will use a closed circle at -1 (indicating that -1 is included in the solution).
3. **Shade the region**: Shade to the left of -1 to indicate all the values less than -1.
### Adjustments
If we want to change the endpoint to open (not included in the solution), we would change the inequality to \(c < -1\), which results in an open circle at -1. However, since the problem requires us to keep \(c \leq -1\), we maintain the closed circle.
#### Final Graph:
- **Closed Circle at \(-1\)**
- **Shaded region to the left extending infinitely.**
This is how you would represent the solution graphically. If you choose to change the inequality and make it \(c < -1\), you would use an open circle.
For the purpose of this solution, since we kept \(c \leq -1\), you will essentially present it as:
- **Closed circle at \(-1\)**.
- **Shaded to the left towards negative infinity**.
1. **Multiply both sides by 6** to eliminate the fraction (since 6 is positive, the direction of the inequality remains the same):
\[
c + 7 \leq 6
\]
2. **Subtract 7 from both sides**:
\[
c \leq 6 - 7
\]
\[
c \leq -1
\]
Now we have the solution:
\[
c \leq -1
\]
This means that the values of \(c\) can include all numbers less than or equal to -1.
### Graphing the Solution
1. **Identify the endpoint**: The endpoint here is \(-1\).
2. **Plot the endpoint**: Since the inequality is \(\leq\), we will use a closed circle at -1 (indicating that -1 is included in the solution).
3. **Shade the region**: Shade to the left of -1 to indicate all the values less than -1.
### Adjustments
If we want to change the endpoint to open (not included in the solution), we would change the inequality to \(c < -1\), which results in an open circle at -1. However, since the problem requires us to keep \(c \leq -1\), we maintain the closed circle.
#### Final Graph:
- **Closed Circle at \(-1\)**
- **Shaded region to the left extending infinitely.**
This is how you would represent the solution graphically. If you choose to change the inequality and make it \(c < -1\), you would use an open circle.
For the purpose of this solution, since we kept \(c \leq -1\), you will essentially present it as:
- **Closed circle at \(-1\)**.
- **Shaded to the left towards negative infinity**.
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