Solve the inequality and graph the solution.
4b–7≥9
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 ---------->
41 answers
To solve the inequality \(4b - 7 \geq 9\):
-
Add 7 to both sides:
\[
4b - 7 + 7 \geq 9 + 7
\]
\[
4b \geq 16
\]
-
Divide both sides by 4:
\[
b \geq 4
\]
The solution to the inequality is \(b \geq 4\).
Graphing the Solution
- The solution includes all values of \(b\) that are greater than or equal to 4.
- Therefore, \(b = 4\) is a closed endpoint because it is included in the solution.
- We will draw a ray starting at 4 and extending to the right (toward positive infinity).
Graph Representation
- Use a closed circle at 4 to indicate that 4 is included, and then draw an arrow extending to the right.
Here's the graph representation:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4(●)--------->
The final representation includes a closed circle at 4 and a ray extending to the right, indicating all values greater than or equal to 4 are included in the solution set.
so it should extend all the way to the 5 on the right? it wasnt just 4 there was a 5 at the right too
Yes, that is correct! The solution \(b \geq 4\) means that the line extends infinitely to the right, including all numbers greater than 4. Here’s how it looks with the endpoint at 4 clearly indicated:
- Start with a closed circle (●) at 4 to show that 4 is included.
- Draw a ray extending to the right, which continues past 5 and towards positive infinity.
Graph Representation
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4(●)--------------------->
The graph illustrates that all values from 4 up to positive infinity are included in the solution, correctly showing that the solution is \(b \geq 4\). The arrow indicates that it goes on indefinitely. Thank you for your clarification!
Solve the inequality and graph the solution.
2–2c<10
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 ---------->
Let's solve the inequality \(2 - 2c < 10\).
Step 1: Solve the Inequality
-
Subtract 2 from both sides:
\[
2 - 2c - 2 < 10 - 2
\]
\[
-2c < 8
\]
-
Divide both sides by -2. Remember, when dividing or multiplying by a negative number, you must flip the inequality sign:
\[
c > \frac{8}{-2}
\]
\[
c > -4
\]
The solution to the inequality is \(c > -4\).
Step 2: Graph the Solution
- The solution includes all values of \(c\) that are greater than -4.
- Since -4 is not included in the solution, we will use an open circle at -4 to indicate that -4 is not part of the solution.
- We then draw a ray extending to the right from -4 to indicate all values greater than -4.
Graph Representation
<------- -5 --------- -4(○)------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 --------->
- The open circle (○) at -4 shows that -4 is not included in the solution.
- The arrow to the right signifies that the solution continues indefinitely to positive infinity.
This graph accurately represents the solution to the inequality \(c > -4\).
which way do i extend it to
For the inequality \(c > -4\), you should extend the ray to the right. Since the solution indicates all values greater than -4, the arrow should be drawn extending towards positive infinity.
Graph Representation
Here is how the complete graph looks:
<------- -5 --------- -4(○)------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 --------->
|
Ray extends to the right
In this graph:
- The open circle (○) at -4 indicates that -4 is not included in the solution.
- The ray extending to the right signifies that all values greater than -4 are part of the solution.
So, the correct way to extend it is to the right from the open circle at -4.
and which number do i stop extending it to? -3? -2? 0?
You do not stop the extension at any specific number when graphing the solution for \(c > -4\). The ray should extend indefinitely to the right, beyond all of those numbers.
In the case of \(c > -4\), it means that all numbers greater than -4 are included in the solution, which extends towards positive infinity:
- The graph does not stop at -3, -2, 0, or any other number—rather, it continues indefinitely to the right.
Final Graph Representation
Here’s a clearer representation:
<------- -5 --------- -4(○)--------------------------->
|
Ray extends to the right, including all numbers greater than -4
So, to clarify, you draw an open circle at \(-4\) and then a ray that extends infinitely to the right without stopping at any specific number, indicating that it includes all values greater than \(-4\).
Solve the inequality and graph the solution.
2m – 9 < –1
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 ---------->
Let's solve the inequality \(2m - 9 < -1\).
Step 1: Solve the Inequality
-
Add 9 to both sides:
\[
2m - 9 + 9 < -1 + 9
\]
\[
2m < 8
\]
-
Divide both sides by 2:
\[
m < \frac{8}{2}
\]
\[
m < 4
\]
The solution to the inequality is \(m < 4\).
Step 2: Graph the Solution
- The solution includes all values of \(m\) that are less than 4.
- Since 4 is not included in the solution, we will use an open circle at 4 to indicate that 4 is not part of the solution.
- We then draw a ray extending to the left from 4 to indicate all values less than 4.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4(○)---------------->
In this graph:
- The open circle (○) at 4 shows that 4 is not included in the solution.
- The ray extends to the left from the open circle at 4, representing all values less than 4.
So, you do not stop the ray at any specific number; it just goes towards negative infinity, indicating that it includes all values less than 4.
Solve the inequality and graph the solution.
3+3u>9
Let's solve the inequality \(3 + 3u > 9\).
Step 1: Solve the Inequality
-
Subtract 3 from both sides:
\[
3 + 3u - 3 > 9 - 3
\]
\[
3u > 6
\]
-
Divide both sides by 3:
\[
u > \frac{6}{3}
\]
\[
u > 2
\]
The solution to the inequality is \(u > 2\).
Step 2: Graph the Solution
- The solution includes all values of \(u\) that are greater than 2.
- Since 2 is not included in the solution, we will use an open circle at 2 to indicate that 2 is not part of the solution.
- We then draw a ray extending to the right from 2 to indicate all values greater than 2.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2(○)--------------------->
In this graph:
- The open circle (○) at 2 shows that 2 is not included in the solution.
- The ray extends to the right from the open circle at 2, representing all values greater than 2.
This properly represents the solution \(u > 2\).
Solve the inequality and graph the solution.
3–7h>10
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(3 - 7h > 10\).
Step 1: Solve the Inequality
-
Subtract 3 from both sides:
\[
3 - 7h - 3 > 10 - 3
\]
\[
-7h > 7
\]
-
Divide both sides by -7. Remember, when dividing or multiplying by a negative number, you must flip the inequality sign:
\[
h < \frac{7}{-7}
\]
\[
h < -1
\]
The solution to the inequality is \(h < -1\).
Step 2: Graph the Solution
- The solution includes all values of \(h\) that are less than -1.
- Since -1 is not included in the solution, we will use an open circle at -1 to indicate that -1 is not part of the solution.
- We then draw a ray extending to the left from -1 to indicate all values less than -1.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1(○)--------------------->
In this graph:
- The open circle (○) at -1 shows that -1 is not included in the solution.
- The ray extends to the left from the open circle at -1, representing all values less than -1.
This correctly represents the solution \(h < -1\).
5f+8≤3
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(5f + 8 \leq 3\).
Step 1: Solve the Inequality
-
Subtract 8 from both sides:
\[
5f + 8 - 8 \leq 3 - 8
\]
\[
5f \leq -5
\]
-
Divide both sides by 5:
\[
f \leq \frac{-5}{5}
\]
\[
f \leq -1
\]
The solution to the inequality is \(f \leq -1\).
Step 2: Graph the Solution
- The solution includes all values of \(f\) that are less than or equal to -1.
- Since -1 is included in the solution, we will use a closed circle at -1 to indicate that -1 is part of the solution.
- We then draw a ray extending to the left from -1 to indicate all values less than -1.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1(●)--------------------->
In this graph:
- The closed circle (●) at -1 shows that -1 is included in the solution.
- The ray extends to the left from the closed circle at -1, representing all values less than or equal to -1.
This graph correctly represents the solution \(f \leq -1\).
–
10+9b<8
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(-10 + 9b < 8\).
Step 1: Solve the Inequality
-
Add 10 to both sides:
\[
-10 + 10 + 9b < 8 + 10
\]
\[
9b < 18
\]
-
Divide both sides by 9:
\[
b < \frac{18}{9}
\]
\[
b < 2
\]
The solution to the inequality is \(b < 2\).
Step 2: Graph the Solution
- The solution includes all values of \(b\) that are less than 2.
- Since 2 is not included in the solution, we will use an open circle at 2 to indicate that 2 is not part of the solution.
- We then draw a ray extending to the left from 2 to indicate all values less than 2.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------ 2(○)--------------------->
Explanation:
- The open circle (○) at 2 shows that 2 is not included in the solution.
- The ray extends to the left from the open circle at 2, representing all values less than 2.
This graph accurately represents the solution \(b < 2\).
8–3c≤2
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(8 - 3c \leq 2\).
Step 1: Solve the Inequality
-
Subtract 8 from both sides:
\[
8 - 3c - 8 \leq 2 - 8
\]
\[
-3c \leq -6
\]
-
Divide both sides by -3. Remember that when dividing by a negative number, you need to flip the inequality sign:
\[
c \geq \frac{-6}{-3}
\]
\[
c \geq 2
\]
The solution to the inequality is \(c \geq 2\).
Step 2: Graph the Solution
- The solution includes all values of \(c\) that are greater than or equal to 2.
- Since 2 is included in the solution, we will use a closed circle at 2 to indicate that 2 is part of the solution.
- We then draw a ray extending to the right from 2 to indicate all values greater than or equal to 2.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------ 2(●)--------------------->
Explanation:
- The closed circle (●) at 2 shows that 2 is included in the solution.
- The ray extends to the right from the closed circle at 2, representing all values greater than or equal to 2.
This graph accurately represents the solution \(c \geq 2\).
Solve the inequality and graph the solution.
2–3u≤5
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(2 - 3u \leq 5\).
Step 1: Solve the Inequality
-
Subtract 2 from both sides:
\[
2 - 2 - 3u \leq 5 - 2
\]
\[
-3u \leq 3
\]
-
Divide both sides by -3. Remember that when dividing by a negative number, you must flip the inequality sign:
\[
u \geq \frac{3}{-3}
\]
\[
u \geq -1
\]
The solution to the inequality is \(u \geq -1\).
Step 2: Graph the Solution
- The solution includes all values of \(u\) that are greater than or equal to -1.
- Since -1 is included in the solution, we will use a closed circle at -1 to indicate that -1 is part of the solution.
- We then draw a ray extending to the right from -1 to indicate all values greater than or equal to -1.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1(●)--------------------->
Explanation:
- The closed circle (●) at -1 shows that -1 is included in the solution.
- The ray extends to the right from the closed circle at -1, representing all values greater than or equal to -1.
This graph accurately represents the solution \(u \geq -1\).
4–4a>8
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Questions
Let's solve the inequality \(4 - 4a > 8\).
Step 1: Solve the Inequality
-
Subtract 4 from both sides:
\[
4 - 4a - 4 > 8 - 4
\]
\[
-4a > 4
\]
-
Divide both sides by -4. Remember, when dividing by a negative number, you must flip the inequality sign:
\[
a < \frac{4}{-4}
\]
\[
a < -1
\]
The solution to the inequality is \(a < -1\).
Step 2: Graph the Solution
- The solution includes all values of \(a\) that are less than -1.
- Since -1 is not included in the solution, we will use an open circle at -1 to indicate that -1 is not part of the solution.
- We then draw a ray extending to the left from -1 to indicate all values less than -1.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1(○)-------------------->
Explanation:
- The open circle (○) at -1 shows that -1 is not included in the solution.
- The ray extends to the left from the open circle at -1, representing all values less than -1.
This graph accurately represents the solution \(a < -1\). If you have any more questions or need further assistance, feel free to ask!
–
q–3≤1
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(q - 3 \leq 1\).
Step 1: Solve the Inequality
- Add 3 to both sides:
\[
q - 3 + 3 \leq 1 + 3
\]
\[
q \leq 4
\]
The solution to the inequality is \(q \leq 4\).
Step 2: Graph the Solution
- The solution includes all values of \(q\) that are less than or equal to 4.
- Since 4 is included in the solution, we will use a closed circle at 4 to indicate that 4 is part of the solution.
- We then draw a ray extending to the left from 4 to indicate all values less than or equal to 4.
Graph Representation
Here’s how the graph looks:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ----- 1 ----- 2 ----- 3 ----- 4(●)--------------------->
Explanation:
- The closed circle (●) at 4 shows that 4 is included in the solution.
- The ray extends to the left from the closed circle at 4, representing all values less than or equal to 4.
This graph accurately represents the solution \(q \leq 4\). If you have any further questions or need additional assistance, feel free to ask!
–
7+5h<8
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Let's solve the inequality \(7 + 5h < 8\).
Step 1: Solve the Inequality
-
Subtract 7 from both sides:
\[
7 + 5h - 7 < 8 - 7
\]
\[
5h < 1
\]
-
Divide both sides by 5:
\[
h < \frac{1}{5}
\]
The solution to the inequality is \(h < \frac{1}{5}\).
Step 2: Graph the Solution
- The solution includes all values of \(h\) that are less than \(\frac{1}{5}\).
- Since \(\frac{1}{5}\) is not included in the solution, we will use an open circle at \(\frac{1}{5}\) to indicate that \(\frac{1}{5}\) is not part of the solution.
- We then draw a ray extending to the left from \(\frac{1}{5}\) to indicate all values less than \(\frac{1}{5}\).
Graph Representation
Here’s how the graph would look:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1/5(○)-------------------->
- Note: The value \(\frac{1}{5}\) is approximately 0.2. Depending on where \(\frac{1}{5}\) lies in your graph, you might want to mark it explicitly if accuracy is important.
Explanation:
- The open circle (○) at \(\frac{1}{5}\) shows that \(\frac{1}{5}\) is not included in the solution.
- The ray extends to the left from the open circle at \(\frac{1}{5}\), representing all values less than \(\frac{1}{5}\).
This graph accurately represents the solution \(h < \frac{1}{5}\). If you have any further questions or need more assistance, feel free to ask!
7+5h<8
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 ---------->
Let's go through the steps to solve the inequality \(7 + 5h < 8\) and represent it graphically based on your instructions.
Step 1: Solve the Inequality
-
Subtract 7 from both sides:
\[
7 + 5h - 7 < 8 - 7
\]
\[
5h < 1
\]
-
Divide both sides by 5:
\[
h < \frac{1}{5}
\]
Step 2: Graph the Solution
- The solution is \(h < \frac{1}{5}\).
- \(\frac{1}{5}\) is equal to 0.2. Since \(0.2\) is not included in the solution, we will use an open circle at \(0.2\) (or more generally, \(\frac{1}{5}\)).
- We then draw a ray extending to the left from \(\frac{1}{5}\) to indicate all values less than \(\frac{1}{5}\).
Graph Representation
Since the number line provided goes from -5 to 5, we can represent it as follows:
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1(○)------- 2 ------ 3 ------ 4 ------ 5 --------->
^
|_____________________________
h < 1/5, which is approximately 0.2
- Closed/open circle: The circle at \( \frac{1}{5} \) (approximately \(0.2\)) is an open circle (○), indicating that \(\frac{1}{5}\) is not included in the solution.
- Ray direction: The ray extends to the left from \( \frac{1}{5} \), indicating all values \(h < \frac{1}{5}\).
Instructions
- Delete the middle of the segment: There’s nothing to delete here in terms of existing values, since we are only focusing on \(h < \frac{1}{5}\).
This graph accurately represents the solution \(h < \frac{1}{5}\). If you have any further questions or want to adjust the representation, feel free to let me know!
Solve the inequality and graph the solution.
4–2r≥8
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
<------- -5 --------- -4 ------ -3 ------- -2 ---- -1 ----- 0 ------ 1 ------- 2 ------ 3 ------ 4 ------- 5 ---------->
use this graph for all the qustions
Let’s solve the inequality \(4 - 2r \geq 8\).
Step 1: Solve the Inequality
-
Subtract 4 from both sides:
\[
4 - 4 - 2r \geq 8 - 4
\]
\[
-2r \geq 4
\]
-
Divide both sides by -2. Remember that dividing by a negative number flips the inequality sign:
\[
r \leq \frac{4}{-2}
\]
\[
r \leq -2
\]
The solution to the inequality is \(r \leq -2\).
Step 2: Graph the Solution
- The solution includes all values of \(r\) that are less than or equal to -2.
- Since -2 is included in the solution, we will use a closed circle at -2 to indicate that -2 is part of the solution.
- We then draw a ray extending to the left from -2 to indicate all values less than or equal to -2.
Graph Representation
Here’s how the graph looks based on your provided number line:
<------- -5 --------- -4 ------ -3 ------- -2(●)--------------------->
- Closed circle at -2: This indicates that -2 is included in the solution.
- Ray: The ray extends to the left from -2, representing all values \(r < -2\).
Summary
The graph accurately represents the solution \(r \leq -2\). If you need any further assistance or have more questions, feel free to ask!
Solve the equation below.
2x + 2 > 10
Group of answer choices
x < 6
x < 4
x > 6
x > 4
Flag question: Question 3
Question 31 pts
Solve the equation below.
2(5x + 8) ≥ 6x + 20.
Group of answer choices
x ≥ 9
x ≥ 1
x ≤ 1
x ≤ 9
Flag question: Question 4
Question 42 pts
Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost $1.30 per pound, and a pumpkin costs $5.20.
Which inequality models this situation, where x is the number of pounds of oranges? Select the correct inequality.
Solve the inequality. How many pounds of oranges can Antoine buy? Select the correct answer.
Group of answer choices
x ≤ 10; Antoine can buy 10 pounds or less of oranges.
1.30x + 5.20 ≤ 18.20
5.20x + 1.30 ≤ 18.20
x ≤ 3; Antoine can buy 3 pounds or less of oranges.
Flag question: Question 5
Question 51 pts
The temperature is 50°F. The temperature will decrease by 4°F each hour. Let h be the number of hours.
When will the temperature be below 32°F?
Write an inequality for this problem.
Group of answer choices
50 + 4h < 32
50 − 4h ≤ 32
50 − 4h < 32
50 + 4h ≤ 32
Let's solve each problem step by step.
Question 1: Solve the inequality \(2x + 2 > 10\).
-
Subtract 2 from both sides:
\[
2x > 8
\]
-
Divide both sides by 2:
\[
x > 4
\]
Correct answer choice: x > 4
Question 2: Solve the inequality \(2(5x + 8) \geq 6x + 20\).
-
Distribute on the left side:
\[
10x + 16 \geq 6x + 20
\]
-
Subtract \(6x\) from both sides:
\[
4x + 16 \geq 20
\]
-
Subtract 16 from both sides:
\[
4x \geq 4
\]
-
Divide both sides by 4:
\[
x \geq 1
\]
Correct answer choice: x ≥ 1
Question 3: Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost $1.30 per pound, and a pumpkin costs $5.20.
Modeling the inequality:
- The cost of oranges is \(1.30x\), where \(x\) is the number of pounds of oranges.
- The cost of the pumpkin is $5.20.
- The total amount spent should be less than or equal to $18.20.
So the correct inequality is:
\[
1.30x + 5.20 \leq 18.20
\]
Solving the inequality:
-
Subtract 5.20 from both sides:
\[
1.30x \leq 13.00
\]
-
Divide by 1.30:
\[
x \leq \frac{13.00}{1.30} \approx 10
\]
Correct answer choice: x ≤ 10; Antoine can buy 10 pounds or less of oranges.
Question 4: The temperature is 50°F. The temperature will decrease by 4°F each hour. Let \(h\) be the number of hours.
Write an inequality for the temperature being below 32°F:
- Start with the initial temperature of 50°F and decrease 4°F for each hour.
- We want to find when it is less than 32°F.
The inequality can be written as:
\[
50 - 4h < 32
\]
Correct answer choice: 50 − 4h < 32
If you have any further questions or need more assistance, feel free to ask!
Solve the equation below.
2x + 2 > 10
Group of answer choices
x < 6
x < 4
x > 6
x > 4
Let's solve the inequality \(2x + 2 > 10\).
Step 1: Solve the Inequality
-
Subtract 2 from both sides:
\[
2x > 10 - 2
\]
\[
2x > 8
\]
-
Divide both sides by 2:
\[
x > \frac{8}{2}
\]
\[
x > 4
\]
Conclusion
The correct answer choice is:
x > 4
Solve the equation below.
2(5x + 8) ≥ 6x + 20.
Group of answer choices
x ≥ 9
x ≥ 1
x ≤ 1
x ≤ 9
Let's solve the inequality \(2(5x + 8) \geq 6x + 20\).
Step 1: Distribute on the left side
- Distribute the 2:
\[
10x + 16 \geq 6x + 20
\]
Step 2: Move all \(x\) terms to one side
- Subtract \(6x\) from both sides:
\[
10x - 6x + 16 \geq 20
\]
\[
4x + 16 \geq 20
\]
Step 3: Isolate \(x\)
-
Subtract 16 from both sides:
\[
4x \geq 20 - 16
\]
\[
4x \geq 4
\]
-
Divide both sides by 4:
\[
x \geq 1
\]
Conclusion
The correct answer choice is:
x ≥ 1
Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost $1.30 per pound, and a pumpkin costs $5.20.
Which inequality models this situation, where x is the number of pounds of oranges? Select the correct inequality.
Solve the inequality. How many pounds of oranges can Antoine buy? Select the correct answer.
Group of answer choices
x ≤ 10; Antoine can buy 10 pounds or less of oranges.
1.30x + 5.20 ≤ 18.20
5.20x + 1.30 ≤ 18.20
x ≤ 3; Antoine can buy 3 pounds or less of oranges.
Flag question: Question 5
Question 51 pts
The temperature is 50°F. The temperature will decrease by 4°F each hour. Let h be the number of hours.
When will the temperature be below 32°F?
Write an inequality for this problem.
Group of answer choices
50 + 4h < 32
50 − 4h ≤ 32
50 − 4h < 32
50 + 4h ≤ 32
just say the answerzs
Question 4:
- Correct inequality: 1.30x + 5.20 ≤ 18.20
- Solution: x ≤ 10; Antoine can buy 10 pounds or less of oranges.
Question 5:
- Correct inequality: 50 − 4h < 32
1 answer