To solve the inequality \( 12 > q + 9 \), we first rearrange it to isolate \( q \):
\[ 12 - 9 > q \]
This simplifies to:
\[ 3 > q \]
or equivalently,
\[ q < 3 \]
This inequality indicates that \( q \) can take on any value less than 3.
Graphing the Solution:
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Identifying the Endpoint: The endpoint of our inequality is 3. We'll plot this point on the number line.
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Choosing Open or Closed: Since the inequality is strictly less than (\(<\)), we will draw an open circle at 3 to indicate that 3 is not included in the solution set.
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Graphing the Ray: From the open circle at 3, we will shade the line to the left (towards smaller numbers) to represent all values less than 3.
Final Graph:
Here’s a simple representation of the graph:
<----(3)---------------->
In this graph:
- The circle at 3 is open (indicating that the value 3 itself is not included).
- The line extends to the left, covering all values less than 3.