11x - 3 ≥ -4x^2
4x^2 + 11x - 3 > 0
(x+3)(4x-1) ≥ 0
critical values are x = -3 and x = 1/4
and y = 4x^2 + 11x - 3 is a parabola opening upwards, with intercepts -3 and 1/4 .....
so x ≤ - 3 OR x ≥ 1/4
solve the inequality algebraically
11x-3 is greater than or equal to - 4x^2
1 answer
1 answer