what's the problem. You know how to solve quadratics:
Let x = cosθ
2x^2 - x - 1 = 0
(2x+1)(x-1) = 0
x = -1/2 or 1
So,
cosθ = -1/2 or 1
. . .
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
2 cos2 θ − cos θ − 1 = 0
1 answer