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Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 de...Asked by Unknowns
solve the following word problem. the air temperature at 9 a.m. is -5.8 degrees celsius. air temperature at noon is -1.6 degrees celsius. what is the change in the temerature during these three hours? write and solve an equation to show your answer. then explain what your answer means.
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Answered by
GPT-4o mini
To find the change in temperature from 9 a.m. to noon, we need to calculate the difference between the temperature at noon and the temperature at 9 a.m.
Let's denote:
- \( T_1 \) as the temperature at 9 a.m. = -5.8°C
- \( T_2 \) as the temperature at noon = -1.6°C
The change in temperature (\( \Delta T \)) can be calculated using the equation:
\[
\Delta T = T_2 - T_1
\]
Now we can substitute in the values:
\[
\Delta T = (-1.6) - (-5.8)
\]
When you subtract a negative number, it's equivalent to adding the positive:
\[
\Delta T = -1.6 + 5.8
\]
Now calculate it:
\[
\Delta T = 4.2
\]
Thus, the change in temperature during these three hours is **4.2 degrees Celsius**.
### Explanation of the Answer:
The positive value of 4.2 degrees Celsius indicates that the temperature increased over the three-hour period from 9 a.m. to noon. Specifically, starting at -5.8°C, the temperature rose to -1.6°C, making it less cold, and the increase of 4.2 degrees shows the actual change in warmth as time went on.
Let's denote:
- \( T_1 \) as the temperature at 9 a.m. = -5.8°C
- \( T_2 \) as the temperature at noon = -1.6°C
The change in temperature (\( \Delta T \)) can be calculated using the equation:
\[
\Delta T = T_2 - T_1
\]
Now we can substitute in the values:
\[
\Delta T = (-1.6) - (-5.8)
\]
When you subtract a negative number, it's equivalent to adding the positive:
\[
\Delta T = -1.6 + 5.8
\]
Now calculate it:
\[
\Delta T = 4.2
\]
Thus, the change in temperature during these three hours is **4.2 degrees Celsius**.
### Explanation of the Answer:
The positive value of 4.2 degrees Celsius indicates that the temperature increased over the three-hour period from 9 a.m. to noon. Specifically, starting at -5.8°C, the temperature rose to -1.6°C, making it less cold, and the increase of 4.2 degrees shows the actual change in warmth as time went on.
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