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Solve the following word problem. The air temperature at 9 a.m. is −5.8 − 5.8 degrees Celsius. The air temperature at noon is −1.6 − 1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.(4 points)

5 answers

To find the change in temperature from 9 a.m. to noon, we can set up the equation using the temperatures at these times.

Let:

  • \( T_1 = -5.8 \) °C (temperature at 9 a.m.)
  • \( T_2 = -1.6 \) °C (temperature at noon)

The change in temperature (\( \Delta T \)) can be calculated using the formula:

\[ \Delta T = T_2 - T_1 \]

Substituting the values we have:

\[ \Delta T = -1.6 - (-5.8) \]

This can be simplified as follows:

\[ \Delta T = -1.6 + 5.8 \]

Now, performing the addition:

\[ \Delta T = 4.2 \]

Thus, the change in temperature during these three hours is \( 4.2 \) degrees Celsius.

Explanation of the Answer:

The answer of \( 4.2 \) °C means that the temperature increased by 4.2 degrees from 9 a.m. to noon. Initially, the temperature was quite cold at −5.8 °C, but by noon, it had warmed up to −1.6 °C. This indicates a significant warming trend in the air temperature over the course of three hours.

make it shorter

To find the change in temperature from 9 a.m. to noon:

Let:

  • \( T_1 = -5.8 \) °C (9 a.m.)
  • \( T_2 = -1.6 \) °C (noon)

The change in temperature (\( \Delta T \)) is calculated as follows:

\[ \Delta T = T_2 - T_1 = -1.6 - (-5.8) = -1.6 + 5.8 = 4.2 \]

Result:

The change in temperature is \( 4.2 \) °C.

Explanation:

This means the temperature increased by 4.2 degrees from −5.8 °C at 9 a.m. to −1.6 °C at noon, indicating a warming trend over three hours.

shorter

To find the change in temperature from 9 a.m. to noon:

Let:

  • \( T_1 = -5.8 \) °C (9 a.m.)
  • \( T_2 = -1.6 \) °C (noon)

Calculate:

\[ \Delta T = T_2 - T_1 = -1.6 - (-5.8) = 4.2 \]

Answer:

The temperature increased by \( 4.2 \) °C from 9 a.m. to noon.