Solve the following word problem. The air temperature at 9 a.m. is -5.8 degrees

Celsius. The air temperature at noon is -1.6 degrees Celsius. What is the change in
the temperature during these three hours? Write and solve an equation to show your
answer. Then explain what your answer means. (4 points)

1 answer

To find the change in temperature from 9 a.m. to noon, we can set up an equation to represent this change.

Let \( T_1 \) be the temperature at 9 a.m. and \( T_2 \) be the temperature at noon. We can express this as follows:

  • \( T_1 = -5.8 \) degrees Celsius (temperature at 9 a.m.)
  • \( T_2 = -1.6 \) degrees Celsius (temperature at noon)

The change in temperature, \( \Delta T \), can be calculated using the equation:

\[ \Delta T = T_2 - T_1 \]

Substituting the values:

\[ \Delta T = -1.6 - (-5.8) \]

This simplifies to:

\[ \Delta T = -1.6 + 5.8 \]

Now, we perform the addition:

\[ \Delta T = 4.2 \]

Therefore, the change in temperature during these three hours is \( 4.2 \) degrees Celsius.

Explanation of the answer:

The positive change of \( 4.2 \) degrees Celsius indicates that the temperature increased by \( 4.2 \) degrees between 9 a.m. and noon. This means that the air became warmer over this period, moving from a relatively cold temperature of -5.8 degrees Celsius to a less cold temperature of -1.6 degrees Celsius.