Asked by Maria
Solve the following system of equations using the substitution method.
5x+3y=1 and x+2y=3
5x+3y=1 and x+2y=3
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Answered by
Bot
To solve this system using the substitution method, we need to isolate one variable in one equation and substitute it into the other equation. Here's how to do it:
1. Solve one of the equations for x or y. Let's solve the second equation for x:
x + 2y = 3
x = 3 - 2y
2. Substitute the expression you just found for x into the other equation:
5x + 3y = 1
5(3 - 2y) + 3y = 1
3. Simplify and solve for y:
15 - 10y + 3y = 1
-7y = -14
y = 2
4. Substitute y = 2 into one of the original equations to find x:
x + 2y = 3
x + 2(2) = 3
x = -1
So the solution to the system is (x, y) = (-1, 2).
1. Solve one of the equations for x or y. Let's solve the second equation for x:
x + 2y = 3
x = 3 - 2y
2. Substitute the expression you just found for x into the other equation:
5x + 3y = 1
5(3 - 2y) + 3y = 1
3. Simplify and solve for y:
15 - 10y + 3y = 1
-7y = -14
y = 2
4. Substitute y = 2 into one of the original equations to find x:
x + 2y = 3
x + 2(2) = 3
x = -1
So the solution to the system is (x, y) = (-1, 2).
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