Question

Solve the following system of equations using the elimination method.

3x−4y=−4
, x+3y=−10

(1 point)
Responses

(−16,2)
left parenthesis negative 16 comma 2 right parenthesis

(−2,−4)
left parenthesis negative 2 comma negative 4 right parenthesis

(−4,−2)
left parenthesis negative 4 comma negative 2 right parenthesis

(−16,−2)
left parenthesis negative 16 comma negative 2 right parenthesis
Skip to navigation
page 15 of 15

Answer 1

To solve the system of equations

1. \(3x - 4y = -4\)
2. \(x + 3y = -10\)

using the elimination method, we will manipulate the equations to eliminate one variable.

First, let's multiply the second equation by 3 so that the coefficients of \(x\) match:

\[
3(x + 3y) = 3(-10)
\]
This gives us:

\[
3x + 9y = -30
\]

Now we have the following two equations:

1. \(3x - 4y = -4\)
2. \(3x + 9y = -30\)

Next, we will subtract the first equation from the second equation to eliminate \(3x\):

\[
(3x + 9y) - (3x - 4y) = -30 - (-4)
\]

This simplifies to:

\[
9y + 4y = -30 + 4
\]
\[
13y = -26
\]

Now, divide both sides by 13:

\[
y = -2
\]

Now that we have the value of \(y\), we can substitute it back into one of the original equations to find \(x\). We'll use the second equation:

\[
x + 3(-2) = -10
\]
\[
x - 6 = -10
\]
\[
x = -10 + 6
\]
\[
x = -4
\]

So the solution to the system of equations is:

\[
(x, y) = (-4, -2)
\]

Thus, the answer is:

\[
\boxed{(-4, -2)}
\]