To solve the system of equations graphically, we will represent both equations on a coordinate plane.
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The first equation is: \[ y = \frac{1}{5}x + 6 \] This is a linear equation in slope-intercept form (y = mx + b) where the slope (m) is \(\frac{1}{5}\) and the y-intercept (b) is 6.
To graph this line:
- Start at the y-intercept (0, 6).
- From the point (0, 6), use the slope \(\frac{1}{5}\) to find another point. For example, for every 5 units you move to the right (increase in x), you move up 1 unit (increase in y), leading to the point (5, 7).
- Plot these points and draw a line through them.
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The second equation is: \[ 4x + 5y = 5 \] To graph this equation, we can solve for y: \[ 5y = 5 - 4x \implies y = -\frac{4}{5}x + 1 \] This is also in slope-intercept form, where the slope is \(-\frac{4}{5}\) and the y-intercept is 1.
To graph this line:
- Start at the y-intercept (0, 1).
- From (0, 1), utilize the slope \(-\frac{4}{5}\). For every 5 units you move to the right, move down 4 units, which gives you the point (5, -3).
- Plot these points and draw a line through them.
Finding the intersection:
To find the solution to the system of equations, we need to determine where the two lines intersect. You can do this by visually analyzing the graph or algebraically by setting the two equations equal to each other.
Solving the equations:
Set the two expressions for y equal to each other: \[ \frac{1}{5}x + 6 = -\frac{4}{5}x + 1 \]
To eliminate fractions, multiply through by 5: \[ x + 30 = -4x + 5 \]
Combine like terms: \[ x + 4x = 5 - 30 \] \[ 5x = -25 \] \[ x = -5 \]
Now, substitute \(x = -5\) back into one of the original equations to find y. Using the first equation: \[ y = \frac{1}{5}(-5) + 6 = -1 + 6 = 5 \]
Conclusion:
The solution to the system of equations is: \[ (x, y) = (-5, 5) \]
So, the point of intersection can be plotted on your graph to show the solution of the system of equations.