First, we need to make the coefficients of either the x term or y term the same in both equations by multiplying one or both equations by a constant. In this case, we can multiply the first equation by 2 to make the coefficients of y the same.
-8x - 16y = -40
8x + 3y = 1
Now we can add the two equations together to eliminate the y variable:
-8x - 16y + 8x + 3y = -40 + 1
-13y = -39
y = 3
Now that we have the value of y, we can substitute it back into one of the original equations to find the value of x:
-4x - 8(3) = -20
-4x - 24 = -20
-4x = 4
x = -1
Therefore, the solution to the system of equations is x = -1, y = 3.
Solve the following system of
equations by elimination.
−4x − 8y = −20
8x + 3y = 1
1 answer